16x^2-48x-8=0

Solution for 16x^2-48x-8=0 equation:

16x^2-48x-8=0

a = 16; b = -48; c = -8;
Δ = b2-4ac
Δ = -482-4·16·(-8)
Δ = 2816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2816}=\sqrt{256*11}=\sqrt{256}*\sqrt{11}=16\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-16\sqrt{11}}{2*16}=\frac{48-16\sqrt{11}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+16\sqrt{11}}{2*16}=\frac{48+16\sqrt{11}}{32}
$